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To prove that the rectangle obtained by bp and dq is equal to the rectangle contained by ab and bc, we will follow these steps: Prove that the rectangle obtained by bp and dq is equal to the rectangle contained ab and bc. Abcd is a parallelogram and apq is a straight line meeting bc at p and dc produced at q.
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We can see that angle ∠ b a p and ∠ c q p are alternate angles. Prove that the rectangle obtained by bp and dq is equal to the rectangle. Prove that the rectangle obtained by bp and dq is equal to the rectangle.
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Abcd is a parallelogram and apq is a straight line meeting bc at p and dc produced at q.
To prove that bp ×dq =ab×bc, we will use properties of parallelograms and similar triangles. Alternate angles are formed when a line crosses two other lines, that lie on opposite sides of the transversal line and on. Understand the given information we have a. Prove that the rectangle obtained by bp and dq is equal to the ab and bc.
Since abcd is a parallelogram, we know that opposite sides are equal and parallel. Abcd is a parallelogram and apq is a straight line meeting bc at pand dc produced at q.
