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If s i n 𝑥 = 𝑎 2 − 𝑏 2 𝑎 2 + 𝑏 2, then the values of tan x, sec x and cosec x if s i n 𝑥 + c o s 𝑥 = 𝑚, then prove that s i n 6 𝑥 + c o s 6 𝑥 = 4 − 3 (𝑚 2 − 1) 2 4, where 𝑚 2 ≤ 2 The value of tan^4 theta+ cot ^4 theta is 2. If tanθ+cotθ = 4, then find the value of tan4θ+cot4θ.

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To find the value of tan4θ+cot4θ given that tanθ+cotθ= x, we can follow these steps: If tan a + cot a = 4, then write the value of tan 4 a + cot 4 a. If tanθ+ cotθ = 2, then what is the value of tan7θ +.

Thus, substituting we get, thus option (a) is the correct option.

If tan a + cot a = 4, then tan 4 a + cot 4 a is equal to. In a triangle abc tan a + tan b + tan c = k what is the value of cot a cot b cot c? Is there an error in this question or solution? If tanθ+ cotθ = 6, then find the value of tan2θ+ cot2θ.

Perimeter of a rectangular field is equal to the perimeter of a triangular field whose sides are in the ratio 3:2:4 respectively. ∴ the value of tan2θ + cot2θ is 14. Is there an error in this question or solution? Lf area of rectangular field is 500 m2 and sides are in.

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यदि tanθ+ cotθ = 6, तो tan2θ+ cot2θ का मान ज्ञात कीजिए।

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